Date: Wed, 14 Nov 2007 15:20:40 +0000 From: Vince <jhary@unsane.co.uk> To: Martin McCormick <martin@dc.cis.okstate.edu> Cc: freebsd-questions@freebsd.org Subject: Re: /bin/sh Can one Easily Strip Path Name from $0? Message-ID: <473B1248.3000502@unsane.co.uk> In-Reply-To: <200711141508.lAEF8veZ083725@m.it.okstate.edu> References: <200711141508.lAEF8veZ083725@m.it.okstate.edu>
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Martin McCormick wrote: > I am ashamed to admit that I have been writing shell > scripts for about 15 years but this problem has me stumped. $0 > is the shell variable which contains the script name or at least > what name is linked to the script. The string in $0 may or may > not contain a path, depending upon how the script was called. It > is easy to strip off the path if it is always there > > #! /bin/sh > PROGNAME=`echo $0 |awk 'BEGIN{FS="/"}{print $NF}'` > echo $PROGNAME > > That beautifully isolates the script name but if you happen to > call the script without prepending a path name such as when the > script is in the execution path, you get an error because there > are no slashes in the string so awk gets confused. > > Is there a better way to always end up with only the script name and > nothing else no matter whether the path was prepended or not? > basename should do it. > Thank you. > > Martin McCormick > _______________________________________________ > freebsd-questions@freebsd.org mailing list > http://lists.freebsd.org/mailman/listinfo/freebsd-questions > To unsubscribe, send any mail to "freebsd-questions-unsubscribe@freebsd.org"
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