Date: Fri, 28 Mar 1997 23:54:52 GMT From: Michael Searle <searle@longacre.demon.co.uk> To: questions@freebsd.org Subject: Re: explain top Message-ID: <m722CAFA5@longacre.demon.co.uk>
next in thread | raw e-mail | index | archive | help
>i can't make any sort of sense out of top's output. in particular, these lines >confuse me: > >Mem: 19M Active, 1944K Inact, 7120K Wired, 49M Cache, 8240K Buf, 128K Free >Swap: 131M Total, 5968K Used, 125M Free, 5% Inuse > >when this machine boots, it says: > >real memory = 83886080 (81920K bytes) >Physical memory hole(s): >avail memory = 79245312 (77388K bytes) > >so, about 77 meg of RAM available. how is that i only have 19M active and 128K >free? > >i really just don't understand what top is telling me, i guess. any tips >appreciated. Because of the other stuff, mainly that 49M cache. 19+2+49+8 ~= 77 meg. -- Michael Searle - searle@longacre.demon.co.uk
Want to link to this message? Use this URL: <https://mail-archive.FreeBSD.org/cgi/mid.cgi?m722CAFA5>