Date: Tue, 01 Dec 1998 11:42:25 +1100 From: Eddie Irvine <eirvine@tpgi.com.au> To: Chris <chrisj@outcast.media-net.net> Cc: freebsd-questions@FreeBSD.ORG Subject: Re: umask Message-ID: <36633B71.40A44BFD@tpgi.com.au> References: <Pine.BSF.3.96.981130183801.9430A-100000@outcast.media-net.net>
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Chris wrote: > > hello. i was wondering if someone could please explain the working of > umask. i understand what it does and what not, just not how to work out > the octal numbers to get the desired result. > Well, consider a umask like, "77x" where x is a number between 1 and 7. The value of x is gotten this way: Start at 0 If we want execute permission, add 1 If you want write permission, add 2 If you want read permission, add 4 So, read and execute will be 1 + 4 = 5, and read and write permission will be 2 + 4 = 6. Any clearer? Eddie. To Unsubscribe: send mail to majordomo@FreeBSD.org with "unsubscribe freebsd-questions" in the body of the message
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