Date: Wed, 29 Mar 2006 14:16:16 -0600 From: Dan Nelson <dnelson@allantgroup.com> To: usleepless@gmail.com Cc: freebsd-questions@freebsd.org, Bill Moran <wmoran@collaborativefusion.com> Subject: Re: Shell ( csh, sh ) scripting and seq-command Message-ID: <20060329201616.GA42429@dan.emsphone.com> In-Reply-To: <c39ec84c0603291150q61988e7fg75f0fe5488f932da@mail.gmail.com> References: <c39ec84c0603290953n2819ef36j30d523537a093827@mail.gmail.com> <c39ec84c0603291043u3557ffa9rb4331ba8d3009cd6@mail.gmail.com> <20060329135713.cec7dbd1.wmoran@collaborativefusion.com> <c39ec84c0603291113k3dbe2d92lb81013f8725c5942@mail.gmail.com> <20060329142754.a7488302.wmoran@collaborativefusion.com> <c39ec84c0603291150q61988e7fg75f0fe5488f932da@mail.gmail.com>
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In the last episode (Mar 29), usleepless@gmail.com said: > > You > > should be able to write a shell script > > as i stated in my message, i lack shell scripting experience. > > > that wraps jot and provides > > its functionality in the same format as seq. > > yes, and to convert steps to reps you will need $reps = ($end - > $start) / $steps, and then see the difference between your script and > the output of an actual linux seq. > > for example: > seq 1 2 60 gives 1..3..5..7..59 ( see also my php and csh implementations ) > > a seq equivalent ( 3 par version ) would be: > > @ reps = ( $3 - $1 ) / $2 > jot $reps $1 $3 > > which will give 1..3..5..7..9..12(!)..zzzz..60 > > so how would your implementation of seq by using jot look like? jot - $1 $3 $2 ( which in your case would be "jot - 1 60 2" ) -- Dan Nelson dnelson@allantgroup.com
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