Date: Wed, 14 Nov 2007 10:19:16 -0500 From: Bill Moran <wmoran@potentialtech.com> To: Martin McCormick <martin@dc.cis.okstate.edu> Cc: freebsd-questions@freebsd.org Subject: Re: /bin/sh Can one Easily Strip Path Name from $0? Message-ID: <20071114101916.c661f4ac.wmoran@potentialtech.com> In-Reply-To: <200711141508.lAEF8veZ083725@m.it.okstate.edu> References: <200711141508.lAEF8veZ083725@m.it.okstate.edu>
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In response to Martin McCormick <martin@dc.cis.okstate.edu>: > I am ashamed to admit that I have been writing shell > scripts for about 15 years but this problem has me stumped. $0 > is the shell variable which contains the script name or at least > what name is linked to the script. The string in $0 may or may > not contain a path, depending upon how the script was called. It > is easy to strip off the path if it is always there > > #! /bin/sh > PROGNAME=`echo $0 |awk 'BEGIN{FS="/"}{print $NF}'` > echo $PROGNAME > > That beautifully isolates the script name but if you happen to > call the script without prepending a path name such as when the > script is in the execution path, you get an error because there > are no slashes in the string so awk gets confused. > > Is there a better way to always end up with only the script name and > nothing else no matter whether the path was prepended or not? basename $0 -- Bill Moran http://www.potentialtech.com
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