Date: Thu, 9 Apr 2009 16:10:28 +0200 From: Polytropon <freebsd@edvax.de> To: freebsd-questions@freebsd.org, lconrad@Go2France.com Cc: lconrad@Go2France.com, Oliver Fromme <olli@lurza.secnetix.de>, freebsd-questions@freebsd.org Subject: Re: awk question Message-ID: <20090409161028.cc669c2d.freebsd@edvax.de> In-Reply-To: <200904091332.n39DWpDs037047@lurza.secnetix.de> References: <200904082253.AA2466447562@mail.Go2France.com> <200904091332.n39DWpDs037047@lurza.secnetix.de>
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On Thu, 9 Apr 2009 15:32:51 +0200 (CEST), Oliver Fromme <olli@lurza.secnetix.de> wrote:
> If ";" is the delimiter character, you need to tell awk
> about it (i.e. use the -F option). This one should work:
>
> awk -F';' '$3 ~ /^[a-z]{5}$/ {print}' file
You can even omit {print} because it's the default action
(to print the whole line, i. e. $0) when no action is given
for a pattern.
% awk -F';' '$3 ~ /^[a-z]{5}$/' file
When using this in a shell, keep an eye on eventually needed
quoting or escaping of $.
--
Polytropon
>From Magdeburg, Germany
Happy FreeBSD user since 4.0
Andra moi ennepe, Mousa, ...
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