Date: Wed, 12 Mar 2003 11:08:52 +0000 From: Matthew Seaman <m.seaman@infracaninophile.co.uk> To: freebsd-questions@FreeBSD.ORG Subject: global regular expression print Message-ID: <20030312110852.GB47126@happy-idiot-talk.infracaninophi> In-Reply-To: <22358.1047465509@www63.gmx.net> References: <22358.1047465509@www63.gmx.net>
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On Wed, Mar 12, 2003 at 11:38:29AM +0100, Pascal Giannakakis wrote:
> Hello,
>
> i want to extract a word with a regular expressions from a line of text.
> Here is what
> i currently have:
>
> grep -c -E 'Interesting ports on [a-zA-Z0-9-.]+ \((.+)\)'
>
> This will print lines (from nmap), but i need only the 1st match in
> parentheses, which
> is the IP in this case. What programm would i use to print what grep sees as
> \1,
> instead of the whole line?
There are any number of solutions to this. Here are two possibilities.
Assuming that lines of interest in the file always start with
'Interesting ports...'
awk '/^Interesting ports on [a-zA-Z0-9-.]+/{ print $5; }' filename
Or more generally:
perl -ne 'm/Interesting ports on [a-zA-Z0-9-.]+ \((.+)\)/ && print "$1\n";' filename
Cheers,
Matthew
--
Dr Matthew J Seaman MA, D.Phil. 26 The Paddocks
Savill Way
PGP: http://www.infracaninophile.co.uk/pgpkey Marlow
Tel: +44 1628 476614 Bucks., SL7 1TH UK
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