Date: Thu, 20 Oct 2005 15:17:17 +0200 From: Emanuel Strobl <Emanuel.strobl@gmx.net> To: freebsd-questions@freebsd.org Subject: (bourne)shell variable names containing a variable? Message-ID: <200510201517.34489@harrymail>
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--nextPart1362382.qEdR5EDavT Content-Type: text/plain; charset="us-ascii" Content-Transfer-Encoding: quoted-printable Content-Disposition: inline Hello, I try to assign a value to a variable, but the variable should consist of=20 another variable. Is this possible (in bourne shell)? Example: #!/bin/sh list=3D"one two three four" for item in $list; do ${item}_present=3Dyes done This doesn't work since the shell tries to execute "one_present=3Dyes"=20 instead of assigning yes to one_present.... What am I missing???? Thanks a lot, =2DHarry --nextPart1362382.qEdR5EDavT Content-Type: application/pgp-signature -----BEGIN PGP SIGNATURE----- Version: GnuPG v1.4.1 (FreeBSD) iD8DBQBDV5juBylq0S4AzzwRAsA6AJ9HwngSeJzfUDJb3hErHDY+2UjwDQCfTyJu j1enWqlQygloijWwjx3edEQ= =UzFQ -----END PGP SIGNATURE----- --nextPart1362382.qEdR5EDavT--
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