Date: Fri, 8 Mar 2002 08:41:14 +0100 From: F.Xavier Noria <fxn@isoco.com> To: "Jon Larssen" <jonlarssen@hotmail.com> Cc: freebsd-questions@FreeBSD.org Subject: Re: find(1) usage Message-ID: <20020308084114.4f110253.fxn@isoco.com> In-Reply-To: <F169kAvjUqMUrYawLLe00013a42@hotmail.com> References: <F169kAvjUqMUrYawLLe00013a42@hotmail.com>
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On Fri, 08 Mar 2002 05:56:02 +0000
"Jon Larssen" <jonlarssen@hotmail.com> wrote:
: Now, I'd like to use the -exec expression of find(1) to obtain the following
: (sample) command:
:
: cp -p /etc/master.passwd backup/etc/master.passwd
:
: I know there's a thingy, {}, that would give the whole path
: (backup/etc/master.passwd, for instance). Now, how can I erase the backup
: part? Is this doable just with clever use of find(1)?
Not clever, but seems to work :-):
$ find backup/ -name '*' -exec \
perl -e '$cur = $bak = shift; $cur =~ s,[^/]*,,; system qq(cp -p "$cur", "$bak")' \
{} \;
I prefer not to use -exec when it is not acting as a filter:
$ find backup/ -name '*' | perl -ne \
'$cur = $bak = $_; $cur =~ s,[^/]*,,; system qq(cp -p "$cur", "$bak")'
-- fxn
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