Date: Sat, 24 Nov 2001 00:31:22 -0600 From: Glenn Johnson <glennpj@charter.net> To: questions@freebsd.org Subject: date conversion in awk Message-ID: <20011124063122.GA2811@gforce.johnson.home>
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I have a set of files that have, as part of their content, dates in the following format: 23-Nov-01 I need to convert the format to: 11/23/2001 I know how to do the conversion with the date command for a single value but I can not quite figure out how to parse through the file with awk to change the format. What I have come up with so far is to extract the date field from the file and save those values in a variable. I then loop over the contents of the variable, do the conversion, and write them out to a file. I then run awk on the original file to get whatever else I need and then paste the results of this and the dates file into another file using the paste command. This works but it seems that I should be able to do the date conversion while in awk without having to write the converted dates out to an intermediate file. Any help appreciated. Thanks. -- Glenn Johnson glennpj@charter.net To Unsubscribe: send mail to majordomo@FreeBSD.org with "unsubscribe freebsd-questions" in the body of the message
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