Date: Tue, 2 Jan 2007 10:20:08 -0800 From: "Kurt Buff" <kurt.buff@gmail.com> To: questions@freebsd.org Subject: Batch file question - average size of file in directory Message-ID: <a9f4a3860701021020g1468af4ah26c8a5fe90610719@mail.gmail.com>
next in thread | raw e-mail | index | archive | help
All, I don't even have a clue how to start this one, so am looking for a little help. I've got a directory with a large number of gzipped files in it (over 110k) along with a few thousand uncompressed files. I'd like to find the average uncompressed size of the gzipped files, and ignore the uncompressed files. How on earth would I go about doing that with the default shell (no bash or other shells installed), or in perl, or something like that. I'm no scripter of any great expertise, and am just stumbling over this trying to find an approach. Many thanks for any help, Kurt
Want to link to this message? Use this URL: <https://mail-archive.FreeBSD.org/cgi/mid.cgi?a9f4a3860701021020g1468af4ah26c8a5fe90610719>