Date: Sat, 03 Nov 2007 13:48:26 +0100 From: Pietro Cerutti <gahr@gahr.ch> To: White Hat <pigskin_referee@yahoo.com> Cc: FreeBSD Users Questions <freebsd-questions@freebsd.org> Subject: Re: Determining the number of files in a directory Message-ID: <472C6E1A.1000408@gahr.ch> In-Reply-To: <538619.51984.qm@web34408.mail.mud.yahoo.com> References: <538619.51984.qm@web34408.mail.mud.yahoo.com>
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White Hat wrote:
> This is probably a dumb question; however, I never let a little thing l=
ike that bother me in the past.
> =20
> Using FreeBSD-6.2 and Bash, how do I determine the number of files in a=
given directory? I have tried all sorts of combinations using different =
flags with the 'ls' command; however, none of them displays the number of=
files in the directory.
> =20
> Other than, by writing a script to accomplish this feat, how could I ac=
hieve my goal?
I find that the most intuitive way is to use something like:
find . -maxdepth 1 | wc -l
Where you can specify how many levels of subdirectories to include in
the count. Please note that count also includes the current directory (".=
").
To exclude hidden files (.*), use
find * -maxdepth 0 | wc -l
or
expr `ls -l | wc -l` - 1
instead.
> =20
> Thanks!
> =20
--=20
Pietro Cerutti
PGP Public Key:
http://gahr.ch/pgp
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