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Date:      Mon, 07 May 2001 11:27:07 -0500
From:      Bob Greene <rgreene@tclme.org>
To:        Greg Lehey <grog@lemis.com>
Cc:        "Andrew C. Hornback" <hornback@wireco.net>, Steve Blanzy <sblanzy@aperion.com>, FreeBSD Questions <questions@FreeBSD.ORG>
Subject:   Re: Raid
Message-ID:  <3AF6CCDB.F1029665@tclme.org>
References:  <000a01c0d57f$2158bb40$0400a8c0@192.168.0.1> <000701c0d581$3dd2da60$0e00000a@tomcat> <20010506101618.B39554@wantadilla.lemis.com> <3AF4BF5A.A03D7278@tclme.org> <20010506130347.F39554@wantadilla.lemis.com>

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Greg Lehey wrote:
> 
> On Saturday,  5 May 2001 at 22:04:58 -0500, Bob Greene wrote:
> > Greg Lehey wrote:
> >>
> >> No, RAID-1 gives you the best performance of any RAID setup. The
> >> reason why you need at least 3 disks for RAID-5 is because it is
> >> slower, and though it would theoretically work with only two disks,
> >> it has no advantages over RAID-1 in this configuration.
> >>
> >
> > Huh?  This paragraph makes no sense.
> >
> > RAID 0 = striped set
> > RAID 1 = mirrored set
> > RAID 5 = striped set with parity
> >
> > RAID 1 gives maximum redundancy, at the cost of two writes.  The third
> > disk in RAID 5 is not a consequence of performance, it's a requirement
> > for redundancy.  RAID 5 with only 2 disks is a failure condition of a 3
> > disk array.  At that point it's effectively just a striped set.
> 
> No, because in degraded 3-disk RAID-5 every third access is intended
> for the failed drive.  In order to read that data, you need to read
> both (all) the other drives and reconstruct it.  This can be very slow
> if you have a large number of drives in the set.
> 
> Greg
> --

Well, you wrote the book; I've only read it.  Is this a vinum specific
performance penalty?

-- 
Bob Greene
rgreene@TclMe.org
Pull my finger for my public key

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