Date: Sun, 13 Feb 2005 20:13:57 +0100 From: =?ISO-8859-1?Q?K=F6vesd=E1n_G=E1bor?= <gabor.kovesdan@t-hosting.hu> To: freebsd-questions@freebsd.org Subject: Crontab script Message-ID: <420FA6F5.1020609@t-hosting.hu>
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Hi,
I've seen somewhere an easy way to check whether a program with a
specified pid is running or not. I've made a crontab script to check my
programs based on this. The script is the following:
#!/bin/sh
PID_FILE="/usr/local/bopm/var/bopm.pid"
PID=`cat $PID_FILE`
EXECUTABLE="/usr/local/bopm/bin/bopm"
if test -r $PID_FILE ; then
# pidfile exist, is it correct?
if `kill -CHLD $PID >/dev/null 2>$1` ; then
# ok, exit silently
exit 0
fi
rm -f $PID_FILE
fi
echo ""
echo "Couldn't find the IRC proxy scanner running, retsarting.."
echo ""
$EXECUTABLE
But unfortunately it starts a new instance of the program even if it is
running. Somebody suggested that I should remove the `` chars from the
line that conatins the kill -CHLD command, because `` are to check the
output, but in this case we are interested in the return value not the
output. The result was the same.
Could You help me please to fix this script? Or if You know an other way
for this job, please tell me.
Cheers,
Gábor
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