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Date:      Wed, 18 Jul 2001 15:05:57 -0700 (PDT)
From:      John Baldwin <jhb@FreeBSD.org>
To:        Etienne de Bruin <et@quidel.com>
Cc:        "freebsd-hackers@freebsd.org" <freebsd-hackers@FreeBSD.org>
Subject:   RE: release.8 (4.3-RELEASE)
Message-ID:  <XFMail.010718150557.jhb@FreeBSD.org>
In-Reply-To: <9D4A4E19244ED4119BE90050DAD5DD47BC5549@mail.quidel.com>

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On 18-Jul-01 Etienne de Bruin wrote:
> I was reading the Makefile in /usr/src/release and wondering about the
> 
> for dir in bin sbin ; do \
>   ln -sf /stand $$dir; \
> done
> 
> part in release.8 - it is my understanding that all that is under /stand is
> linked to files in $$dir.
> 
> What does this accomplish?

No, it links $$dir to /stand.  This creates /sbin and /bin directories so that
you can still see /bin/ls even though ls is really in /stand/ls.  This is to
make a "normal" path work right, and to allow scripts which assume the default
location of utilities work.

-- 

John Baldwin <jhb@FreeBSD.org> -- http://www.FreeBSD.org/~jhb/
PGP Key: http://www.baldwin.cx/~john/pgpkey.asc
"Power Users Use the Power to Serve!"  -  http://www.FreeBSD.org/

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