Date: Wed, 24 Aug 2005 14:39:51 GMT From: Stepan Koltsov <yozh@mx1.ru> To: freebsd-gnats-submit@FreeBSD.org Subject: bin/85267: sh -e exits when command "false || return 1" appears in function Message-ID: <200508241439.j7OEdpvE030606@www.freebsd.org> Resent-Message-ID: <200508241440.j7OEeEsP025544@freefall.freebsd.org>
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>Number: 85267
>Category: bin
>Synopsis: sh -e exits when command "false || return 1" appears in function
>Confidential: no
>Severity: non-critical
>Priority: low
>Responsible: freebsd-bugs
>State: open
>Quarter:
>Keywords:
>Date-Required:
>Class: sw-bug
>Submitter-Id: current-users
>Arrival-Date: Wed Aug 24 14:40:14 GMT 2005
>Closed-Date:
>Last-Modified:
>Originator: Stepan Koltsov
>Release: 5.4
>Organization:
>Environment:
FreeBSD grep.po.cs.msu.su 5.4-RELEASE-p2 FreeBSD 5.4-RELEASE-p2 #3: Thu Jun 16 19:39:43 MSD 2005 root@phobos.cs.msu.su:/usr/obj/usr/src/sys/GREP i386
>Description:
Command "false || return 1" in function causes sh to exit if "set -e" is turned on.
>How-To-Repeat:
Script
===
#!/bin/sh -e
set -e
f() {
false || return 1
return 0
}
f || true
===
prints "the end" in bash and in zsh (and should print I believe), but prints nothing and exists with error in sh.
>Fix:
>Release-Note:
>Audit-Trail:
>Unformatted:
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