Date: Mon, 28 May 2001 13:59:49 -0700 (PDT) From: patl@Phoenix.Volant.ORG To: Mike Meyer <mwm@mired.org> Cc: Jim Conner <jconner@enterit.com>, Duke Normandin <01031149@3web.net>, questions@freebsd.org Subject: Re: Need help with Bash function Message-ID: <ML-3.4.991083589.5627.patl@asimov.phoenix.volant.org> In-Reply-To: <15122.32514.853271.557888@guru.mired.org>
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On 28-May-01 at 09:39, Mike Meyer (mwm@mired.org) wrote:
> Jim Conner <jconner@enterit.com> types:
> > The only thing you are lacking is quotes in your condition...
> >
> > function ezq() {
> > if [ -a "~/tmp/*" ]
> > then
> > echo -e "there's something here....\n"
> > else
> > echo -e "empty....\n"
> > fi
> > }
> >
> > Now, I ususally use ksh but bash should be able to do the same thing.
>
> That doesn't work in bash here. I suspect that the version of test
> built into ksh and bash are different. Just out of curiosity, did you
> test it with more than one file in ~/tmp?
I missed the beginning of the thread; so I'm not sure what the actual
goal is; but you should be able to use:
if [ $(ls -a /tmp | wc -l) -eq 2 ]
then
echo "empty...\n"
else
echo "there's something here...\n"
fi
Note that this form also detects hidden files (those starting with
a period.) To ignore them, change the test to:
if [ $(ls /tmp | wc -l) -eq 0 ]
If you want to be absolutely certain that you're using the built-in
version of test, use
if builtin [ $(ls ...
-Pat
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