Date: Tue, 14 Mar 2000 13:34:12 -0800 (PST) From: <keith@mail.telestream.com> To: Dan Nelson <dnelson@emsphone.com> Cc: freebsd-questions@FreeBSD.ORG Subject: Re: silly off topic scripting question Message-ID: <Pine.LNX.4.10.10003141327440.31160-100000@mail.telestream.com> In-Reply-To: <20000314144600.A97517@dan.emsphone.com>
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Didn't work like you suggested but it sparked me to think of a way that
did. So thanks. Here is how I did it.
for instance in $LIST
do
NEWDATA=${NAME[17]} < This is an array index that is the dynamic portion.
PREVDATA=$TOTAL
TOTAL=$PREVDATA:$NEWDATA
done
echo $TOTAL
Keith
=================================
I here by change the name
of RedHat to RedSplat.
Keith W.
At the helm <for better or worse>
=================================
On Tue, 14 Mar 2000, Dan Nelson wrote:
> In the last episode (Mar 14), keith@mail.telestream.com said:
> > How can one append a variable in BASH? Like run a loop and have the
> > results of the loop append a variable instead of just resetting the
> > variable with the new result?
> > I have the bash book and don't seem to see this discussed anywhere.
>
> $ newdata=hello
> $ var=test
> $ var=$var$newdata
> $ echo $var
>
> testhello
> $
>
> --
> Dan Nelson
> dnelson@emsphone.com
>
>
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