Date: Tue, 1 Aug 2006 11:57:24 -0300 (ADT) From: User Freebsd <freebsd@hub.org> To: Nikolas Britton <nikolas.britton@gmail.com> Cc: Xiao-Yong Jin <xj2106@columbia.edu>, freebsd-questions@freebsd.org Subject: Re: Gotta start somewhere ... how many of us are really out there? Message-ID: <20060801115051.N27679@ganymede.hub.org> In-Reply-To: <ef10de9a0608010121j154c7ael7ece0997a479572e@mail.gmail.com> References: <20060728164526.E27679@ganymede.hub.org> <87slklj9hu.fsf@photon.homelinux.org> <20060729021007.F27679@ganymede.hub.org> <44CD41EC.6030605@freebsd.org> <20060730233839.I27679@ganymede.hub.org> <44CDAA98.3030702@freebsd.org> <44CDE02F.4090604@dial.pipex.com> <44CE7DD0.9070902@childeric.freeserve.co.uk> <871ws1v261.fsf@photon.homelinux.org> <20060731220830.B27679@ganymede.hub.org> <ef10de9a0608010121j154c7ael7ece0997a479572e@mail.gmail.com>
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On Tue, 1 Aug 2006, Nikolas Britton wrote: > Generating a unique anonymous key is easy, proving why we need it is not. If you want to make accurate #s, you need to make sure that a host doesn't send in multiple reports, which means you need a unique key for each host ... IP doesn't work, since NAT'd networks would all use the same IP ... even non-NAT'd networks would have the risk of being on dynamic IPs, so that again doesn't work ... > (20 + 32) bytes * (10^7) = 495.910645 megabytes. The FreeBSD team would > need a 6.6Mbit/s uplink to handle peak load assuming 50% of the hosts > are set to UTC/GMT time and all trigger within 5 minutes of each > other.... I'm not going to pay for that connection. First question is ... what is 10^7? # of reporting hosts? Where are you getting that # from? Second, that is assuming *all* FreeBSD servers reported ... But, I'll say this right now ... *if* something like this could be implemented to give us accurate #s, I *would* be willing to absorb the bandwidth you are talking about to see it happen ... ---- Marc G. Fournier Hub.Org Networking Services (http://www.hub.org) Email . scrappy@hub.org MSN . scrappy@hub.org Yahoo . yscrappy Skype: hub.org ICQ . 7615664
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