Date: Sat, 29 Jun 1996 00:31:31 -0400 From: Max Karesev <maxy@haven.ios.com> To: questions@freebsd.org Subject: FreeBSD_Q Message-ID: <199606290431.AAA25832@haven.ios.com>
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Dear Walnut Creek! I have installed FreeBSD on my PC and I have the following problem. BSD is installed on master hard drive (1083.8Mb) and shares the drive with DOS. DOS partition is located at the beginning of the drive and ends properly so that BSD's /root is within the first 1024 cylinders. However, it seems that disk giometry is wrong. BSD only boots IF it was the default. Otherwise, if the default is DOS and I press F2 for BSD, it hangs, and I only can bootstrap from a floppy and then notify the kernel about the boot partition. My hard drive is WD Caviar AC21000. According to its manual, it has 2100 actual cyls, 16 heads, 63 sect./track. And it is the same as was initially recognized by CMOS setup. However, when installing BSD, the partition manager gives me this geometry: 525 cyls, 64 heads, 63 sect. It does not work. Neither does the manual-given geometry. Another detail: Norton Utilities says: 64 sides, 524 tracks, 63 sect/trk. Which (if any) is correct geometry? How can I figure it out? I tried a number of possible geometries. Are there any tools which could give me the correct info? Why does Norton say "524" while BSD says "525"? I am stuck.
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