Date: Thu, 1 Jul 2010 20:49:14 -0400 From: "b. f." <bf1783@googlemail.com> To: Aiza <aiza21@comclark.com> Cc: freebsd-questions@FreeBSD.org Subject: Re: Bourne .sh ? Message-ID: <AANLkTike3XX-sXiGM1LrMNpmjJ5rRGwB2tHpgbQ7DIIw@mail.gmail.com>
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>I have a file containing this
>
>drwxrwxr-x 14 89987 546 512 Jun 6 2009 7.2-RELEASE
>drwxrwxr-x 14 89987 546 512 Mar 23 04:59 7.3-RELEASE
>drwxrwxr-x 13 89987 546 512 Nov 23 2009 8.0-RELEASE
>drwxrwxr-x 13 89987 546 512 Jul 1 04:56 8.1-RC2
>
>I want to strip off everything to the left of the release
>version so I end up with this.
>
>7.2-RELEASE
>7.3-RELEASE
>8.0-RELEASE
>8.1-RC2
>
>How would I code to do this?
By using something like:
awk '{print $9}' nameofmyfile
(Or whatever column it is, if not the ninth.) Or you can use sed(1).
Or cut(1). Or colrm(1)...
I'd recommend first reading some of the base system manpages, and
tutorials on basic text processing tools and shell programming than
can be found in many places on the web, before addressing a lot of
questions like this to a FreeBSD-specific list.
Regards,
b.
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