Date: Tue, 4 Jul 2000 17:37:45 +0100 From: Mark Ovens <mark@ukug.uk.freebsd.org> To: Christoph Sold <so@server.i-clue.de> Cc: Willem Brown <willem@brwn.org>, Christoph Sold <so@server.ms-agentur.de>, FreeBSD-Questions@freebsd.org Subject: Re: find -exec Problem Message-ID: <20000704173745.D233@parish> In-Reply-To: <39610086.FC0AAEF6@i-clue.de>; from so@server.i-clue.de on Mon, Jul 03, 2000 at 11:07:18PM %2B0200 References: <3960FC7A.4217804D@i-clue.de> <20000703225424.C15794@snoopy.brwn.org> <39610086.FC0AAEF6@i-clue.de>
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On Mon, Jul 03, 2000 at 11:07:18PM +0200, Christoph Sold wrote:
>
>
> Willem Brown wrote:
> >
> > Hi,
> >
> > On Mon, Jul 03, 2000 at 10:50:02PM +0200, Christoph Sold wrote:
> > > Maybe it's just me, but... could some helpful soul look at the
> > > following:
> > >
> > > # uname -a
> > > FreeBSD me.here.org 3.4-STABLE FreeBSD 3.4-STABLE #7: Thu Jun 22
> > > 14:30:20 CEST 2000 root@me.here.org:/usr/src/sys/compile/ME i386
> > > # find . -type d -print -exec 'chmod o+rx {}';
> >
> > I think you should escape the semi-colon. This worked for me:
> >
> > find . -type d -print -exec ls -l {} \;
>
> # find . -type d -print -exec chmod o+rx {} \;
>
> Worked. Removed quotes from problem above... worked. Dunno why.
>
Because everything after ``-exec'' up to the ``\;'' is passed as
*separate* args to exec(3). Using the single quotes made the whole
thing into a single arg.
> Thanks
> -Christoph
>
> --
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