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Date:      Wed, 12 Jan 2000 22:01:57 -0500 (EST)
From:      Garrett Wollman <wollman@khavrinen.lcs.mit.edu>
To:        Garance A Drosihn <drosih@rpi.edu>
Cc:        Garrett Wollman <wollman@khavrinen.lcs.mit.edu>, "Rodney W. Grimes" <freebsd@gndrsh.dnsmgr.net>, current@FreeBSD.ORG
Subject:   Re: Additional option to ls -l for large files
Message-ID:  <200001130301.WAA76792@khavrinen.lcs.mit.edu>
In-Reply-To: <v0421010ab4a2b121c34e@[128.113.24.47]>
References:  <200001120201.SAA26378@gndrsh.dnsmgr.net> <v04210106b4a296b28cc2@[128.113.24.47]> <200001122151.QAA75948@khavrinen.lcs.mit.edu> <v0421010ab4a2b121c34e@[128.113.24.47]>

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<<On Wed, 12 Jan 2000 17:45:51 -0500, Garance A Drosihn <drosih@rpi.edu> said:

> Yes, it may be "more pure" to use 1024 when comparing 'ls' listings
> to block counts, but it is less confusing WITHIN a single 'ls -l'
> listing if all the numbers are decimal, and not some combination of
> base-10 and base-2.

OK, let's try again.

BLOCKSIZE=1000 ls -s

Actually, this doesn't quite do what one would want, either -- the
remainder is always rounded up, so a file which takes 1024 bytes even
shows up as two 1000-blocks.  However, it does do the right thing for
large block sizes:

wollman@khavrinen$ BLOCKSIZE=1M df /
Filesystem   1M-blocks     Used    Avail Capacity  Mounted on
/dev/wd0s1a         93       28       56    34%    /
wollman@khavrinen$ BLOCKSIZE=1000000 df /
Filesystem   1000000-blocks     Used    Avail Capacity  Mounted on
/dev/wd0s1a              97       30       59    34%    /

-GAWollman



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