Date: Thu, 14 Aug 2014 10:13:54 -0400 From: Rick Miller <vmiller@hostileadmin.com> To: FreeBSD Questions <freebsd-questions@freebsd.org> Subject: /bin/sh script not behaving as expected Message-ID: <CAHzLAVE1E8hZvZEnDko8-7cfx6JYypezi3oxs4vKKjxDzSzZnw@mail.gmail.com>
next in thread | raw e-mail | index | archive | help
Hi all,
I have shell code whose purpose is to determine the first disk in the
system where FreeBSD is to be installed. The code is not behaving as
expected and I=E2=80=99m hoping that fresh pairs of eyes might help me iden=
tify the
problem.
Here is the script along with an explanation of the implementation and
description of the problem:
#! /bin/sh
disks=3D"da2 da1 da0";
for d in ${disks}; do
if [ -z "${disk}" -o "${disk}" '>' "${d}" ]; then
: ${disk:=3D${d}};
fi
done
echo $disk;
# Given the input(s), $disks, the expected behavior of the above code is to
# set $disk to "da0" which ends up being the chosen disk to install FreeBSD=
.
#
# The for() loop iterates over $disks. The if() statement tests the status
of
# $disk; If $disk is unset/null, $disk is set to $d. If $disk is set, it
# compares the binary value of $disk to $d and should select the element
with
# the lower binary value. In this particular case, it is expected to selec=
t
# da0 as the ultimate value for $disk, but in practice, it appears to set
# $disk to da2 instead.
#
# NOTE: This is on FreeBSD 10. The code has been tested in bash as well,
which
# returns the same results.
TIA
--=20
Take care
Rick Miller
Want to link to this message? Use this URL: <https://mail-archive.FreeBSD.org/cgi/mid.cgi?CAHzLAVE1E8hZvZEnDko8-7cfx6JYypezi3oxs4vKKjxDzSzZnw>