Date: Wed, 01 Nov 2000 11:56:43 -0800 From: Kent Stewart <kstewart@urx.com> To: 8773836928@skytel.com Cc: freebsd-questions@FreeBSD.ORG Subject: Re: vi question Message-ID: <3A00757B.D444AED0@urx.com> References: <200011014727.589586540@skytel.com>
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8773836928@skytel.com wrote: > > Hello, > > I have been editing some > Perl scripts in vi recently, > and I find it very annoying > that Perl cannot comment > blocks of code, only lines. > > I have been reading the docs in vi, but I can't quite figure out how to do a substitute command that will, say, prepend a # to the next n lines, and later remove the # ( well, the second one I could always use :s and replace the first # with nothing for the next n lines. But the first one is still a mystery to me ). The regular expression for the beginning of a line is ^ and the end of the line is $. If you are in column 1 on line 1, you can :.,$s/^/#/ To remove the #, you would :.,$s/^#// HTH, Kent > > Any insight would be greatly appreciated. > > Thanks! > > P.S. Please cc: me, as I am not subscribed to the list with this account. Thanks again. > > To Unsubscribe: send mail to majordomo@FreeBSD.org > with "unsubscribe freebsd-questions" in the body of the message -- Kent Stewart Richland, WA mailto:kbstew99@hotmail.com http://kstewart.urx.com/kstewart/index.html FreeBSD News http://daily.daemonnews.org/ To Unsubscribe: send mail to majordomo@FreeBSD.org with "unsubscribe freebsd-questions" in the body of the message
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