Date: Fri, 19 Jul 2019 07:55:36 +0000 From: Alexey Dokuchaev <danfe@freebsd.org> To: Brooks Davis <brooks@freebsd.org> Cc: Piotr Kubaj <pkubaj@anongoth.pl>, Piotr Kubaj <pkubaj@freebsd.org>, svn-ports-head@freebsd.org, svn-ports-all@freebsd.org, ports-committers@freebsd.org Subject: Re: svn commit: r506850 - head/databases/mysql-connector-odbc Message-ID: <20190719075536.GA15828@FreeBSD.org> In-Reply-To: <20190718174824.GB16600@spindle.one-eyed-alien.net> References: <201907181130.x6IBU0lF065180@repo.freebsd.org> <20190718120720.GB59568@FreeBSD.org> <20190718121709.GA38485@ThinkPad-X200.g.anongoth.pl> <20190718124236.GA96440@FreeBSD.org> <20190718174824.GB16600@spindle.one-eyed-alien.net>
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On Thu, Jul 18, 2019 at 05:48:24PM +0000, Brooks Davis wrote: > On Thu, Jul 18, 2019 at 12:42:36PM +0000, Alexey Dokuchaev wrote: > > On Thu, Jul 18, 2019 at 02:17:09PM +0200, Piotr Kubaj wrote: > > > Ah, I didn't know it existed. > > > > > > But C++0x is still the same as C++11... > > > > *sigh* > > > > Yes, their effect is the same (both would pull the same compiler), > > but it gives the reader false impression that the code is C++11 while > > it's C++0x. > > C++11 is literally the-standard-formerly-known-as-C++0x. To the extent > that there are deviations, it's because the compiler is referring to > some (probably unstated and inconsistent) draft. While I agree that C++11 is essentially a gold-release version of C++0x, I was trying to make a larger point here, that is, do not blindly use `c++11-lang' or `c11' whenever a modern compiler is required and try to do something more appropriate in each particular case. ./danfe
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